Optimal. Leaf size=243 \[ \frac{n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f-b \left (\sqrt{e^2-4 d f}+e\right )}\right )}{\sqrt{e^2-4 d f}}+\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (-\sqrt{e^2-4 d f}+e+2 f x\right )}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (\sqrt{e^2-4 d f}+e+2 f x\right )}{2 a f-b \left (\sqrt{e^2-4 d f}+e\right )}\right )}{\sqrt{e^2-4 d f}} \]
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Rubi [A] time = 0.228893, antiderivative size = 243, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 4, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.174, Rules used = {2418, 2394, 2393, 2391} \[ \frac{n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f-b \left (\sqrt{e^2-4 d f}+e\right )}\right )}{\sqrt{e^2-4 d f}}+\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (-\sqrt{e^2-4 d f}+e+2 f x\right )}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (\sqrt{e^2-4 d f}+e+2 f x\right )}{2 a f-b \left (\sqrt{e^2-4 d f}+e\right )}\right )}{\sqrt{e^2-4 d f}} \]
Antiderivative was successfully verified.
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Rule 2418
Rule 2394
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int \frac{\log \left (c (a+b x)^n\right )}{d+e x+f x^2} \, dx &=\int \left (\frac{2 f \log \left (c (a+b x)^n\right )}{\sqrt{e^2-4 d f} \left (e-\sqrt{e^2-4 d f}+2 f x\right )}-\frac{2 f \log \left (c (a+b x)^n\right )}{\sqrt{e^2-4 d f} \left (e+\sqrt{e^2-4 d f}+2 f x\right )}\right ) \, dx\\ &=\frac{(2 f) \int \frac{\log \left (c (a+b x)^n\right )}{e-\sqrt{e^2-4 d f}+2 f x} \, dx}{\sqrt{e^2-4 d f}}-\frac{(2 f) \int \frac{\log \left (c (a+b x)^n\right )}{e+\sqrt{e^2-4 d f}+2 f x} \, dx}{\sqrt{e^2-4 d f}}\\ &=\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e-\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e+\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{(b n) \int \frac{\log \left (\frac{b \left (e-\sqrt{e^2-4 d f}+2 f x\right )}{-2 a f+b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{a+b x} \, dx}{\sqrt{e^2-4 d f}}+\frac{(b n) \int \frac{\log \left (\frac{b \left (e+\sqrt{e^2-4 d f}+2 f x\right )}{-2 a f+b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{a+b x} \, dx}{\sqrt{e^2-4 d f}}\\ &=\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e-\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e+\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{n \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 f x}{-2 a f+b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{x} \, dx,x,a+b x\right )}{\sqrt{e^2-4 d f}}+\frac{n \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{2 f x}{-2 a f+b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{x} \, dx,x,a+b x\right )}{\sqrt{e^2-4 d f}}\\ &=\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e-\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{\log \left (c (a+b x)^n\right ) \log \left (-\frac{b \left (e+\sqrt{e^2-4 d f}+2 f x\right )}{2 a f-b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}+\frac{n \text{Li}_2\left (\frac{2 f (a+b x)}{2 a f-b \left (e-\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}-\frac{n \text{Li}_2\left (\frac{2 f (a+b x)}{2 a f-b \left (e+\sqrt{e^2-4 d f}\right )}\right )}{\sqrt{e^2-4 d f}}\\ \end{align*}
Mathematica [A] time = 0.181706, size = 194, normalized size = 0.8 \[ \frac{n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f+b \left (\sqrt{e^2-4 d f}-e\right )}\right )-n \text{PolyLog}\left (2,\frac{2 f (a+b x)}{2 a f-b \left (\sqrt{e^2-4 d f}+e\right )}\right )+\log \left (c (a+b x)^n\right ) \left (\log \left (\frac{b \left (\sqrt{e^2-4 d f}-e-2 f x\right )}{2 a f+b \sqrt{e^2-4 d f}+b (-e)}\right )-\log \left (\frac{b \left (\sqrt{e^2-4 d f}+e+2 f x\right )}{b \left (\sqrt{e^2-4 d f}+e\right )-2 a f}\right )\right )}{\sqrt{e^2-4 d f}} \]
Antiderivative was successfully verified.
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Maple [C] time = 0.446, size = 689, normalized size = 2.8 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\log \left ({\left (b x + a\right )}^{n} c\right )}{f x^{2} + e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log{\left (c \left (a + b x\right )^{n} \right )}}{d + e x + f x^{2}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left ({\left (b x + a\right )}^{n} c\right )}{f x^{2} + e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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